Question

пассажирский поезд проходит расстояние между городами за 5 ч. Скорость которого на 40 км/ч больше,проходит это же расстояние за 3 ч. какова скорость скорого поезда? дайте ответ в км/ч.​

Answer 1

Ответ:

Скорость скорого поезда 100 км/час.

Пошаговое объяснение:

Возьмем за х скорость скорого поезда, а скорость пассажирского получается х-40

5*(х-40)=3х

5х-200=3х

2х=200

х=100

Answer 2

Ответ:

100 км/ч

Пошаговое объяснение:

Скорость пассажирского поезда обозначим за v. Тогда скорость скорого будет v+40.

Пассажирский поезд проходит расстояние за 5*v, а скорый за 3*( v+40)

Речь идёт об одном м том же расстоянии, поэтому

5v = 3(v+40)

2v=120

v = 60 км/ч

Скорость скорого поезда 60+40=100 км/ч

Answer 3

Calculation of the Speed of the Faster Train

To find the speed of the faster train, we can set up a system of equations based on the given information.

Let's assume the distance between the cities is d kilometers.

According to the problem, the slower train takes 5 hours to cover this distance, while the faster train takes 3 hours to cover the same distance.

Let's denote the speed of the slower train as s km/h. Therefore, the speed of the faster train would be s + 40 km/h, as it is stated that the faster train's speed is 40 km/h more than the slower train.

Using the formula speed = distance / time, we can set up the following equations:

Equation 1: s = d / 5 (since the slower train takes 5 hours to cover the distance)

Equation 2: s + 40 = d / 3 (since the faster train takes 3 hours to cover the distance)

To solve this system of equations, we can substitute the value of s from Equation 1 into Equation 2:

d / 5 + 40 = d / 3

Now, let's solve this equation to find the value of d:

d / 5 + 40 = d / 3

Multiplying both sides of the equation by 15 to eliminate the denominators:

3d + 600 = 5d

Subtracting 3d from both sides:

600 = 2d

Dividing both sides by 2:

d = 300

Therefore, the distance between the cities is 300 kilometers.

Now, let's substitute this value of d into Equation 1 to find the speed of the slower train:

s = 300 / 5

s = 60 km/h

So, the speed of the slower train is 60 km/h.

Finally, let's calculate the speed of the faster train:

faster train's speed = slower train's speed + 40

faster train's speed = 60 + 40

faster train's speed = 100 km/h

Therefore, the speed of the faster train is 100 km/h.

Please note that the calculations are based on the given information and assumptions made.