Question

9) 0,01 (2,2x-0,1) + 0, 1 (x-100) =​

Answer 1

Ответ:

0,01 (2,2x-0,1) + 0, 1 (x-100)=

0.022х-0.001+0.1х-10=

0.122х-10.001

Пошаговое объяснение:

Answer 2

It appears that you have an equation that you'd like to solve. Let's solve it step by step:

0.01(2.2x - 0.1) + 0.1(x - 100) = 0

First, distribute the constants within the parentheses:

0.022x - 0.001 + 0.1x - 10 = 0

Now, combine like terms on the left side of the equation:

(0.022x + 0.1x) - 0.001 - 10 = 0

0.122x - 0.001 - 10 = 0

Next, add 10 to both sides of the equation to isolate the x terms:

0.122x - 0.001 - 10 + 10 = 0 + 10

0.122x - 0.001 = 10

Now, add 0.001 to both sides to get rid of the -0.001 term on the left side:

0.122x - 0.001 + 0.001 = 10 + 0.001

0.122x = 10.001

Finally, divide both sides by 0.122 to solve for x:

(0.122x) / 0.122 = 10.001 / 0.122

x = 82.01

So, the solution to the equation is:

x ≈ 82.01