Question

1)7+9x/4+2-x/9=7x+1 2)5(x+5)+3(x+2)-7(x+6)=x 3)5(x+5)+3(x+2)-7(x+4 3/7)=x

Answer 1

Ответ:

1) х =175/288

Пошаговое объяснение:

7+2-1=7х-9х/4+х/9

8=(252-81+4) х/36

8*36=175х

Х=175/288

И так далее в том же духе

Answer 2

Let's solve each of these equations step by step:

1. $7 + \frac{9x}{4} + 2 - \frac{x}{9} = 7x + 1$

First, let's get rid of the fractions by finding a common denominator, which is 36:

$36 \cdot (7 + \frac{9x}{4} + 2 - \frac{x}{9}) = 36 \cdot (7x + 1)$

Now, we have:

$36 \cdot 7 + 36 \cdot \frac{9x}{4} + 36 \cdot 2 - 36 \cdot \frac{x}{9} = 36 \cdot 7x + 36 \cdot 1$

Simplify both sides:

$252 + 9 \cdot 9x + 72 - 4x = 252x + 36$

Combine like terms:

$324 + 5x = 252x + 36$

Subtract $252x$ from both sides:

$324 + 5x - 252x = 36$

Combine like terms again:

$-247x + 324 = 36$

Now, subtract 324 from both sides:

$-247x = 36 - 324$

$-247x = -288$

Divide both sides by -247 to isolate x:

$x = \frac{-288}{-247}$

$x \approx 1.166$

So, the solution to the first equation is approximately $x \approx 1.166$.

2. $5(x+5) + 3(x+2) - 7(x+6) = x$

Let's simplify and solve for x:

$5x + 25 + 3x + 6 - 7x - 42 = x$

Combine like terms:

$5x + 3x - 7x + 25 + 6 - 42 = x$

$x - 11 = x$

Now, subtract x from both sides:

$-11 = 0$

This equation is inconsistent, which means there is no solution. The variables cancel out, leaving an equation that is always false ($-11 = 0$).

3. $5(x+5) + 3(x+2) - 7(x+\frac{31}{7}) = x$

First, let's simplify the equation:

$5x + 25 + 3x + 6 - 7\left(x + \frac{31}{7}\right) = x$

Now, distribute the -7 on the left side:

$5x + 25 + 3x + 6 - 7x - \frac{217}{7} = x$

Combine like terms:

$x + 31 - \frac{217}{7} = x$

Now, subtract x from both sides:

$31 - \frac{217}{7} = 0$

To solve for x, let's first get rid of the fraction by multiplying both sides by 7:

$7 \cdot 31 - 217 = 0$

$217 - 217 = 0$

$0 = 0$

This equation is always true (0 = 0), which means that there are infinitely many solutions for x. In other words, any value of x will satisfy this equation.