Question

3x2-2(x2-2x)+2x-11=5

Answer 1

Ответ:

На фото

Пошаговое объяснение:

.............................

Answer 2

Ответ:

на фото ...........

Пошаговое объяснение:

x=5..........

Answer 3

To solve the equation 3x^2 - 2(x^2 - 2x) + 2x - 11 = 5, follow these steps:

1. Distribute the -2 on the left side of the equation:

   3x^2 - 2x^2 + 4x + 2x - 11 = 5

2. Combine like terms on the left side of the equation:

   (3x^2 - 2x^2) + (4x + 2x) - 11 = 5

   x^2 + 6x - 11 = 5

3. Move the constant term 5 to the right side of the equation by subtracting 5 from both sides:

   x^2 + 6x - 11 - 5 = 0

   x^2 + 6x - 16 = 0

4. Now, you have a quadratic equation in the form ax^2 + bx + c = 0, where a = 1, b = 6, and c = -16. To solve for x, you can use the quadratic formula:

   x = (-b ± √(b^2 - 4ac)) / (2a)

   Plugging in the values:

   x = (-6 ± √(6^2 - 4(1)(-16))) / (2(1))

   x = (-6 ± √(36 + 64)) / 2

   x = (-6 ± √100) / 2

   x = (-6 ± 10) / 2

Now, you can find two possible solutions for x:

1. x = (-6 + 10) / 2 = 4 / 2 = 2
2. x = (-6 - 10) / 2 = -16 / 2 = -8

So, the solutions to the equation 3x^2 - 2(x^2 - 2x) + 2x - 11 = 5 are x = 2 and x = -8.