Question

Вычислите y’(-1), если y=x^3-3x+2

Answer 1

Решение:
y=x^3-3x+2
у'(х) = 3х^2 - 3 + 0 = 3х^2 - 3.
у'(- 1) = 3•( - 1)^2 - 3 = 3•1 - 3 = 0.
Ответ: 0.

Answer 2

y'=3x^2-3

y'(-1)=3*(-1)^2-3 = 3*1-3=3-3=0

Answer 3

To find y'(-1), we need to compute the derivative of the function y(x) with respect to x and then evaluate it at x = -1.

The given function is: y(x) = x^3 - 3x + 2

To find y'(x), we take the derivative of each term separately:

d/dx (x^3) = 3x^2 d/dx (-3x) = -3 d/dx (2) = 0 (the derivative of a constant is always 0)

Now, the derivative of y(x) is the sum of the derivatives of each term:

y'(x) = 3x^2 - 3

To find y'(-1), we simply substitute x with -1:

y'(-1) = 3(-1)^2 - 3 y'(-1) = 3(1) - 3 y'(-1) = 3 - 3 y'(-1) = 0

Therefore, y'(-1) = 0.