Question

2*sin^2pi/6-корень 3*cos pi/6-2*cos^2pi/3

Answer 1

Ответ:-1.5

Пошаговое объяснение:=2×(1/4)^2-корень из 3×корень из 3/2-(-2)×1/4=-1.5

Sin^2pi/6=(1/2)^2

Cos pi/6=корень из 3/2

Cos^2pi/3=(1/2)^2

Answer 2

Ответ:-1.5

Пошаговое объяснение:=2×(1/4)^2-корень из 3×корень из 3/2-(-2)×1/4=-1.5

Sin^2pi/6=(1/2)^2

Cos pi/6=корень из 3/2

Cos^2pi/3=(1/2)^2

Answer 3

Let's simplify the expression step by step:

1. Simplify angles inside trigonometric functions:

   • sin(π/6) = 1/2
   • cos(π/6) = √3/2
   • cos(π/3) = 1/2

2. Rewrite the expression with the simplified values: 2sin^2(π/6) - √3cos(π/6) - 2*cos^2(π/3)

3. Substitute the values: 2*(1/2)^2 - √3*(√3/2) - 2*(1/2)^2

4. Simplify the expression further: 2*(1/4) - √3*(√3/2) - 2*(1/4)

   = 1/2 - 3/2 - 1/2

5. Combine the terms: = (-2)

So, the simplified expression is -2.