Question

Дана функция f(x)=x^3+2x^2-3x+4. Найти f(0), f(1), f(-1), f(2).​

Answer 1

f(0)=0^3+2*0^2-3*0+4=4

f(1)=1^3+2*1^2-3*1+4=4

f(-1)=-1^3+2*(-1)^2-3*(-1)+4=10

f(2)=2^3+2*2^2-3*2+4=14

Answer 2

To find the values of the given function f(x) for specific values of x, simply substitute the values into the expression for f(x).

Given function: f(x) = x^3 + 2x^2 - 3x + 4

1. f(0): f(0) = (0)^3 + 2(0)^2 - 3(0) + 4 f(0) = 0 + 0 - 0 + 4 f(0) = 4

2. f(1): f(1) = (1)^3 + 2(1)^2 - 3(1) + 4 f(1) = 1 + 2 - 3 + 4 f(1) = 4

3. f(-1): f(-1) = (-1)^3 + 2(-1)^2 - 3(-1) + 4 f(-1) = -1 + 2 + 3 + 4 f(-1) = 8

4. f(2): f(2) = (2)^3 + 2(2)^2 - 3(2) + 4 f(2) = 8 + 8 - 6 + 4 f(2) = 14

So, the values of the function for the given inputs are:

f(0) = 4 f(1) = 4 f(-1) = 8 f(2) = 14