Question

(4-С)²+(2-С)(2+C) при с=- ⅜​

Answer 1

Ответ:(4-с)^2+(2-с)(2+с)=16-8с+с^2+4-с^2=20-8с    

при с=-3/8     20-8*(-3/8)=20-(-3)=20+3=23

Пошаговое объяснение:

Answer 2

To evaluate the expression (4-C)² + (2-C)(2+C) when C = -3/8, we simply substitute the value of C into the expression and perform the calculations:

(4 - C)² + (2 - C)(2 + C)

When C = -3/8:

(4 - (-3/8))² + (2 - (-3/8))(2 + (-3/8))

Now, let's simplify the expression:

(4 + 3/8)² + (2 + 3/8)(2 - 3/8)

(4 + 3/8)² + (2 + 3/8)(2 - 3/8) is equal to:

(4 + 3/8)² + (2 + 3/8)(2 - 3/8) = (4 + 3/8)² + (2 + 3/8)(2 - 3/8)

Now, let's calculate each part:

(4 + 3/8)² = (32/8 + 3/8)² = (35/8)² = 1225/64

(2 + 3/8)(2 - 3/8) = (16/8 - 9/64) = (16/8 - 9/64) = (127/64)

Now, add both parts:

(4 + 3/8)² + (2 + 3/8)(2 - 3/8) = 1225/64 + 127/64 = (1225 + 127)/64 = 1352/64 = 169/8

So, the value of the expression (4-C)² + (2-C)(2+C) when C = -3/8 is 169/8.