Question

Решите уравнение (12y+18)*(1,6-0,4y)=0

Answer 1

Ответ:

(12у + 18)(1,6-0,2у) = 0 Разбиваем на два уравнения:

12у + 18 = 0 1,6 - 0,2у = 0

у = - 18/12 = -1,5 у = 1,6/0,2 = 8

Ответ: -1,5; 8.

Answer 2

To solve the equation (12y + 18) * (1.6 - 0.4y) = 0, we need to find the values of y that make the equation true.

The equation is a product of two factors equated to zero, so it will be satisfied if either of the factors is equal to zero. Therefore, we have two cases:

1. (12y + 18) = 0
2. (1.6 - 0.4y) = 0

Let's solve each case:

Case 1: (12y + 18) = 0

Subtract 18 from both sides: 12y = -18

Divide by 12: y = -18 / 12 y = -1.5

Case 2: (1.6 - 0.4y) = 0

Subtract 1.6 from both sides: -0.4y = -1.6

Divide by -0.4 (which is the same as multiplying by -2.5): y = (-1.6) / (-0.4) y = 4

So, the solutions to the equation are y = -1.5 and y = 4.