Question

(x-5)²-x(x+4)=11 vott.......

Answer 1

Ответ:

1

Пошаговое объяснение:

(x-5)²-x(x+4)=11

x²-10x+25-x²-4x-11=0

-14x+14=0

-14x=-14

x=1

Answer 2

It seems like you have an equation that you'd like to solve:

$(x-5)^2 - x(x+4) = 11$.

Let's work through the steps to solve for $x$:

1. Expand the expressions: $(x-5)^2 = x^2 - 10x + 25$, $x(x+4) = x^2 + 4x$.

2. Substitute the expanded expressions into the equation: $x^2 - 10x + 25 - x^2 - 4x = 11$.

3. Simplify: $-14x + 25 = 11$.

4. Subtract 25 from both sides: $-14x = -14$.

5. Divide by -14: $x = 1$.

So, the solution to the equation is $x = 1$. You can verify this by substituting $x = 1$ back into the original equation to see if it holds true.