Question

3x2-x+2+3x2-x+3x2-x+1=93

Answer 1

Ответ:

x= 10/3;    x= -3

Пошаговое объяснение:

3x²-x+2+3x²-x+3x²-x+1=93

9x²-3x+3=93

x² - x/3 + 1/3 = 31/3

x² - x/3 = 10

(x - 1/6)² = 361/36

x - 1/6 = 19/6;    x - 1/6 = - 19/6

x= 10/3;    x= -3

Answer 2

To solve the equation 3x^2 - x + 2 + 3x^2 - x + 3x^2 - x + 1 = 93, you can follow these steps:

1. Combine like terms on the left side of the equation:

   3x^2 + 3x^2 + 3x^2 - x - x - x + 2 + 1 = 93

   This simplifies to:

   9x^2 - 3x + 3 = 93

2. Subtract 3 from both sides of the equation to isolate the quadratic terms:

   9x^2 - 3x = 93 - 3

   This simplifies to:

   9x^2 - 3x = 90

3. Divide both sides of the equation by the common factor of 3:

   (9x^2 - 3x)/3 = 90/3

   This simplifies to:

   3x^2 - x = 30

4. Now, you have a quadratic equation in the form ax^2 + bx + c = 0. Set it equal to zero:

   3x^2 - x - 30 = 0

5. To solve this quadratic equation, you can use the quadratic formula:

   x = (-b ± √(b^2 - 4ac)) / (2a)

   In this case, a = 3, b = -1, and c = -30. Plug these values into the formula:

   x = (-(-1) ± √((-1)^2 - 4 * 3 * (-30))) / (2 * 3)

   x = (1 ± √(1 + 360)) / 6

6. Now, calculate the two possible solutions:

   x₁ = (1 + √361) / 6 x₁ = (1 + 19) / 6 x₁ = 20 / 6 x₁ = 10/3

   x₂ = (1 - √361) / 6 x₂ = (1 - 19) / 6 x₂ = (-18) / 6 x₂ = -3

So, the solutions to the equation 3x^2 - x + 2 + 3x^2 - x + 3x^2 - x + 1 = 93 are x₁ = 10/3 and x₂ = -3.