Question

Найти производную функцию y=x^2-4

Answer 1

Ответ:

y'=2x

Пошаговое объяснение:

$y=x^2-4\\y'=(x^2-4)'=2x\\y'=2x$

$c'=0$ , где c - любое число

$(x^n)'=nx^{n-1}$

$(cx)'=c$

$(cx^n)'=c*nx^{n-1}$

Answer 2

Calculating the Derivative of y = x^2 - 4

To find the derivative of the function y = x^2 - 4, we can use the power rule of differentiation. According to the power rule, if we have a function of the form f(x) = x^n, the derivative is given by f'(x) = n * x^(n-1).

In this case, we have y = x^2 - 4, where n = 2. Applying the power rule, we get:

y' = 2 * x^(2-1) = 2x

Therefore, the derivative of the function y = x^2 - 4 is y' = 2x.

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