Question

Решите ПЖ задания, если сложно то не делайте вас некто не заставляет это делать!!! 1.Запишите какую нибудь десятичную дробь, расположеную между числами 20,4 и 20,5.Ответ запишите двумя знаками после запятой. 2. В школе 98 пятиклассников. Пять седьмых всех пятиклассников поехали на экскурсию в музей, а остальные пошли в театр. пятиклассников пошло в театр? 3. От посёлка до города, расстояние между которым 27 км, велосипедист проехал за полтора часа, а мотоциклист на час быстрее. На сколько километров в час скорость мотоциклиста больше скорости велосипедиста? Запишите решение и ответ. 4. На овошной базе 2ц картофеля раскладывают в пакеты по 3 кг. Сколько киллограммов картофеля осталось некпакованым? 4. Деревянный брус размером 10 см x 10см x 1050см распилили на одинаковые пластины для паркета. Каждая пластина имеет размер 2 см x 10см x 15см. Сколько пластин получилось из этого бруска? 5. У пяти одноклассников было поровну наклеек с футболистами, причём всего у них было больше 110,но меньше 160 наклеек. Когда в их класс пришёл новый ученик, каждый мальчик подарил ему седьмую часть своих наклеек. Сколько наклеек отдал каждый? Запишите решение и ответ. ​

Answer 1

Ответ:

1.20<20.47<20.5

2.28

3. 540

4.1

5. 76

на последний вопрос не смог ответить

Пошаговое объяснение:

это конечно возможно не правильно, не вините меня если не правильно, я пытался

Answer 2

1. To find a decimal number between 20.4 and 20.5, we can take the average of these two numbers. The average of 20.4 and 20.5 is 20.45. Therefore, a decimal number between 20.4 and 20.5 is 20.45.

2. In a school, there are 98 fifth-grade students. Five-sevenths of all the fifth-grade students went on a museum excursion, while the rest went to the theater. To find out how many fifth-grade students went to the theater, we can calculate the difference between the total number of students and the number of students who went on the excursion.

The number of fifth-grade students who went on the excursion is calculated as follows: (5/7) * 98 = 70. Therefore, the number of fifth-grade students who went to the theater is: 98 - 70 = 28.

3. A cyclist traveled a distance of 27 km from a village to a city in 1.5 hours. The motorcyclist traveled the same distance in 1 hour less than the cyclist. We need to find the difference in speed between the motorcyclist and the cyclist.

To find the speed of the cyclist, we divide the distance by the time: 27 km / 1.5 hours = 18 km/h. The motorcyclist traveled the same distance in 1 hour less, so the time taken by the motorcyclist is 1.5 - 1 = 0.5 hours. To find the speed of the motorcyclist, we divide the distance by the time: 27 km / 0.5 hours = 54 km/h.

Therefore, the speed of the motorcyclist is 54 km/h, which is 36 km/h faster than the speed of the cyclist.

4. There are 2 tons (2000 kg) of potatoes on a vegetable base, and they are packed into bags of 3 kg each. We need to find the weight of the unpacked potatoes.

To find the weight of the unpacked potatoes, we need to divide the total weight of the potatoes by the weight of each bag: 2000 kg / 3 kg = 666.67 bags. Since we cannot have a fraction of a bag, we need to round down to the nearest whole number. Therefore, the number of bags is 666.

To find the weight of the unpacked potatoes, we multiply the number of bags by the weight of each bag: 666 bags * 3 kg/bag = 1998 kg.

Therefore, the weight of the unpacked potatoes is 1998 kg.

5. Five classmates had an equal number of football stickers, with a total number of stickers between 110 and 160. When a new student joined their class, each boy gave him one-seventh of their stickers. We need to find out how many stickers each boy gave away.

Let's assume that each boy had x stickers. The total number of stickers is between 110 and 160, so we can set up the following inequality: 110 ≤ 5x ≤ 160.

To find the number of stickers each boy gave away, we need to divide the total number of stickers by the number of boys: x/7.

Since we don't have an exact value for x, we can find the range of stickers each boy gave away by substituting the minimum and maximum values for x into the equation.

For the minimum value of x (110/5 = 22), each boy gave away 22/7 = 3 stickers. For the maximum value of x (160/5 = 32), each boy gave away 32/7 ≈ 4.57 stickers.

Therefore, each boy gave away between 3 and 4 stickers.