Question

У трикутнику АВС ∠C=90° . Висота СР утворює з катетом АС кут ,що дорівнює 38°. Знайдіт гострі кути трикутника ?

Answer 1

Ответ:

з трикутника АВС (кут С = 90*)

кут А = 180*- кут АС - кут С = 180-38-90=52

з трикутника АВС (кут С = 90*)

кут В = 180*- (кут С + кут А) = 180-90-52=38

Объяснение:

відповідь: 52,38,кут С = 90

Answer 2

Given Information:

We are given a triangle ABC with angle C measuring 90°. The height CR forms an angle with the leg AC that measures 38°.

Solution:

To find the acute angles of the triangle, we can use the fact that the sum of the angles in a triangle is always 180°.

Let's denote the acute angles of the triangle as ∠A and ∠B.

Since angle C is 90°, we have: ∠A + ∠B + ∠C = 180°

Substituting the given values, we have: ∠A + ∠B + 90° = 180°

Simplifying the equation, we get: ∠A + ∠B = 90°

Now, we know that the height CR forms an angle of 38° with the leg AC. This means that angle ACR is 38°.

Since angle ACR is a right angle (90°) and angle A is adjacent to it, we can use the property of complementary angles to find angle A: ∠A + ∠ACR = 90°

Substituting the given value, we have: ∠A + 38° = 90°

Simplifying the equation, we get: ∠A = 90° - 38° ∠A = 52°

Now, we can find angle B by subtracting angle A from 90°: ∠B = 90° - ∠A ∠B = 90° - 52° ∠B = 38°

Therefore, the acute angles of the triangle ABC are ∠A = 52° and ∠B = 38°.

Note: The source provided does not contain specific information related to this problem. The solution is derived based on the properties of triangles and angles.