Question

2. Складіть рівняння кола із центром у точці Q, радіус якого дорівнює r, якщо Q (4; -3); r=13 срочно​

Answer 1

Equation of a Circle with Center at Point Q

The equation of a circle with center at point Q and radius r can be written in the standard form as:

`(x - a)^2 + (y - b)^2 = r^2`

where (a, b) represents the coordinates of the center of the circle.

In this case, the center of the circle is given as Q(4, -3) and the radius is given as r = 13. Therefore, the equation of the circle can be written as:

`(x - 4)^2 + (y - (-3))^2 = 13^2`

Simplifying further:

`(x - 4)^2 + (y + 3)^2 = 169`

So, the equation of the circle with center at Q(4, -3) and radius 13 is `(x - 4)^2 + (y + 3)^2 = 169`.

Please let me know if you need any further assistance!