Question

Пожалуйста помогите СРОЧНООО! Пусть ВАС подобен EFD. Стороны АВ = 3 см, ВС = 4 см, АС = 5 см, DE = 3, 3 см и EF = 4, 4 см. Найди DF

Answer 1

Ответ:

5,5

Объяснение:

находим коэффициент подобия

k=AB\DE=BC\EF= 3\3,3=4\4,4=0,9090909090909091

k=0,9090909090909091

k=AC\DF следовательно DF=AC\k=5\0,9090909090909091 =5,5

Answer 2

Calculation of DF in a Triangle

To find the length of DF in the given triangle, we can use the triangle inequality theorem. According to this theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

In this case, we have a triangle with sides AB, BC, and AC measuring 3 cm, 4 cm, and 5 cm respectively. We also have line segments DE and EF measuring 3.3 cm and 4.4 cm respectively.

To find DF, we need to determine the length of the side that connects points D and F. Let's assume DF = x cm.

Using the triangle inequality theorem, we can set up the following inequalities:

1. DF + DE > EF 2. DF + EF > DE 3. DE + EF > DF

Substituting the given values, we have:

1. x + 3.3 > 4.4 2. x + 4.4 > 3.3 3. 3.3 + 4.4 > x

Simplifying these inequalities, we get:

1. x > 4.4 - 3.3 2. x > 3.3 - 4.4 3. 3.3 + 4.4 > x

1. x > 1.1 2. x > -1.1 3. 7.7 > x

From these inequalities, we can see that x must be greater than 1.1 and less than 7.7.

Therefore, the length of DF falls within the range of 1.1 cm < DF < 7.7 cm.