Question

Решить с полным решением(все расписать) 1) (х-1)(х+2)=0 2) х(х+0,5)(х-8)=0 3)x^{2}-9х=0

Answer 1

Надеюсь, что про первое и второе вы пошутили.

$(x-1)(x+2) = 0 x1 = 1 ; x2 = -2$

$x(x+0,5)(x-8) = 0$
$x - 8 = 0 ; x = 0 ; x + 0,5 = 0$
$x1 = 8 ; x2 = 0 ; x3 = -0,5$

$x^2 - 9x = 0 x(x - 9) = 0 x - 9 = 0 ; x = 0 x1 = 9 ; x2 = 0$

Answer 2

1) (х-1)(х+2)=0

To solve the equation (х-1)(х+2)=0, we need to find the values of x that make the equation true.

We can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.

So, we set each factor equal to zero and solve for x:

Factor 1: х-1=0 Adding 1 to both sides of the equation, we get: х=1

Factor 2: х+2=0 Subtracting 2 from both sides of the equation, we get: х=-2

Therefore, the solutions to the equation (х-1)(х+2)=0 are x=1 and x=-2.

2) х(х+0.5)(х-8)=0

To solve the equation х(х+0.5)(х-8)=0, we again use the zero product property.

Setting each factor equal to zero and solving for x:

Factor 1: х=0 This gives us one solution: x=0.

Factor 2: х+0.5=0 Subtracting 0.5 from both sides of the equation, we get: х=-0.5

Factor 3: х-8=0 Adding 8 to both sides of the equation, we get: х=8

Therefore, the solutions to the equation х(х+0.5)(х-8)=0 are x=0, x=-0.5, and x=8.

3) x^2-9x=0

To solve the equation x^2-9x=0, we can factor out x from the equation:

x(x-9)=0

Now, we can use the zero product property and set each factor equal to zero:

Factor 1: x=0 This gives us one solution: x=0.

Factor 2: x-9=0 Adding 9 to both sides of the equation, we get: x=9

Therefore, the solutions to the equation x^2-9x=0 are x=0 and x=9.

Please let me know if you need any further assistance!