Question

Сократить дробь, разложив предварительно числитель и знаменатель на множители. числитель:(1) 12х-3 знаменатель 24х^2-6х (2) числитель: у+5 знаменатель: y^2+10y+25. (3)числ: а^2-4а+4 знам:a^2-4 (4) числ: n^2-n+1 знам: n^3-n^2+n УМОЛЯЮ СДЕЛАЙТЕ ПОЖАЛУЙСТА ПО БЫСТРЕЕ ДАМ 39 БАЛЛОВ

Answer 1

Решение в приложении к ответу

Answer 2

Simplifying Fractions

1. Simplify the fraction: - Numerator: \(12x-3\) - Denominator: \(24x^2-6x\)

To simplify the fraction, we need to factor the numerator and the denominator and then cancel out any common factors.

The numerator can be factored as \(3(4x-1)\), and the denominator can be factored as \(6x(4x-1)\). Therefore, the fraction simplifies to:

\(\frac{12x-3}{24x^2-6x} = \frac{3(4x-1)}{6x(4x-1)}\)

Cancelling out the common factor \((4x-1)\), we get:

\(\frac{3}{6x} = \frac{1}{2x}\).

2. Simplify the fraction: - Numerator: \(u+5\) - Denominator: \(y^2+10y+25\)

The denominator can be factored as \((y+5)^2\). Therefore, the fraction simplifies to:

\(\frac{u+5}{y^2+10y+25} = \frac{u+5}{(y+5)^2}\).

3. Simplify the fraction: - Numerator: \(a^2-4a+4\) - Denominator: \(a^2-4\)

The numerator can be factored as \((a-2)^2\), and the denominator can be factored as \((a+2)(a-2)\). Therefore, the fraction simplifies to:

\(\frac{a^2-4a+4}{a^2-4} = \frac{(a-2)^2}{(a+2)(a-2)}\)

Cancelling out the common factor \((a-2)\), we get:

\(\frac{a-2}{a+2}\).

4. Simplify the fraction: - Numerator: \(n^2-n+1\) - Denominator: \(n^3-n^2+n\)

The fraction cannot be further simplified as there are no common factors between the numerator and the denominator.

I hope this helps! If you have further questions, feel free to ask.