Question

-x2+6x+16=0 помогите пожалуйста

Answer 1

D=36+4*16=100
x1=(-6+10)\-2=-2
x2=(-6-10)\-2=8

Answer 2

Solving the Quadratic Equation -x^2 + 6x + 16 = 0

To solve the quadratic equation -x^2 + 6x + 16 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

where a, b, and c are the coefficients of the quadratic equation.

Applying the Quadratic Formula

Using the coefficients from the given equation -x^2 + 6x + 16 = 0, we have: a = -1, b = 6, and c = 16.

Plugging these values into the quadratic formula, we get:

x = (-6 ± √(6^2 - 4*(-1)*16)) / (2*(-1))

Calculating the Solutions

Now, let's calculate the solutions for x using the quadratic formula:

x = (-6 ± √(36 + 64)) / (-2)

x = (-6 ± √100) / (-2)

x = (-6 ± 10) / (-2)

So, the solutions for x are:

x = (-6 + 10) / (-2) = 4 / (-2) = -2

x = (-6 - 10) / (-2) = -16 / (-2) = 8

Therefore, the solutions for the given quadratic equation -x^2 + 6x + 16 = 0 are x = -2 and x = 8.