Question

Известно,что ig 2=a, lg 3=b.Выразите lg 24 через a и b.просьба жизни и смерти!!!!!!

Answer 1

log24=lg(3*8)=lg8*lg3=3lg2+lg3=3a+b

Answer 2

lg24 = lg(8*3) = lg8+lg3 =lg(2^3) +lg3 = 3lg2+lg3 =3a+b

Answer 3

Expressing lg 24 in terms of a and b

To express lg 24 in terms of a and b, we can use the properties of logarithms. First, we need to express 24 as a power of 2 and 3, since lg 2 = a and lg 3 = b.

We know that 24 can be expressed as 2^3 * 3^1. Therefore, we can rewrite lg 24 as lg (2^3 * 3^1).

Using the properties of logarithms, lg (2^3 * 3^1) can be expressed as 3 * lg 2 + lg 3.

Substituting the given values, lg 2 = a and lg 3 = b, we get: lg 24 = 3 * a + b

lg 24 = 3a + b