Question

Помогите пожалуйста решить систему уравнений 2x^2-y=2 X-y=1 Заранее большое спасибо

Answer 1

У меня такие корни получились

Answer 2

Вроде вот так получается..........

Answer 3

Solving the System of Equations

To solve the system of equations: 1. 2x^2 - y = 2 2. x - y = 1

We can use the substitution method or the elimination method. Let's use the substitution method.

First, we solve the second equation for x: x = y + 1

Now we substitute this value of x into the first equation: 2(y + 1)^2 - y = 2

Expanding and simplifying: 2(y^2 + 2y + 1) - y = 2 2y^2 + 4y + 2 - y = 2 2y^2 + 3y = 0

Now we can solve for y by factoring: y(2y + 3) = 0 So, y = 0 or y = -3/2

Now that we have the values of y, we can find the corresponding values of x using the equation x = y + 1.

When y = 0, x = 0 + 1 = 1 When y = -3/2, x = -3/2 + 1 = -1/2

Therefore, the solution to the system of equations is: x = 1, y = 0 x = -1/2, y = -3/2

These are the solutions to the given system of equations.