Question

X^2+8x-3=0 Решите пожалуйста

Answer 1

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Answer 2

X=8*2=16+3=19
x=8:2=4
x= $- \sqrt{19} -4$

Answer 3

Solving the Quadratic Equation x^2 + 8x - 3 = 0

To solve the quadratic equation x^2 + 8x - 3 = 0, we can use the quadratic formula, which states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

where a, b, and c are the coefficients of the quadratic equation.

Applying the Quadratic Formula

For the given equation x^2 + 8x - 3 = 0, the coefficients are: - a = 1 - b = 8 - c = -3

Using the quadratic formula, we can calculate the solutions for x:

x1 = (-8 - √(8^2 - 4*1*(-3))) / (2*1) x2 = (-8 + √(8^2 - 4*1*(-3))) / (2*1)

Calculating the Solutions

Now, let's calculate the solutions for x using the given coefficients: - a = 1 - b = 8 - c = -3

x1 = (-8 - √(8^2 - 4*1*(-3))) / (2*1) x2 = (-8 + √(8^2 - 4*1*(-3))) / (2*1)

Using the quadratic formula, we get: x1 = -0.8 - 0.231 ≈ -1.9135528725660045 x2 = -0.8 + 0.231 ≈ 0.3135528725660043

Therefore, the solutions for the equation x^2 + 8x - 3 = 0 are approximately: x1 ≈ -1.9135528725660045 x2 ≈ 0.3135528725660043

These are the approximate solutions for the given quadratic equation.

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