Question

помогите ( игрик-4)(игрик+4)= (7х-2)(7х+2)=

Answer 1

игрик квадрат - 16

49 икс квадрат - 4

Answer 2

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I can help you with this math problem. Here is the detailed solution:

To simplify the expression $(y-4)(y+4)=(7x-2)(7x+2)$, we can use the following steps:

1. Expand the brackets using the distributive property. We get $y^2-16=49x^2-28x-28x+4$. 2. Subtract $y^2$ from both sides and rearrange the terms. We get $0=49x^2-56x-y^2+20$. 3. Factor the quadratic equation in terms of $x$. We get $0=(7x-10)(7x+2)-y^2$. 4. Use the zero product property to find the possible values of $x$. We get $x=\frac{10}{7}$ or $x=-\frac{2}{7}$. 5. Substitute the values of $x$ into the original equation and solve for $y$. We get $y=\pm 6$ or $y=\pm 2\sqrt{13}$.

Therefore, the possible solutions are $(\frac{10}{7},6)$, $(\frac{10}{7},-6)$, $(-\frac{2}{7},2\sqrt{13})$, and $(-\frac{2}{7},-2\sqrt{13})$.Ответь+подробно.+помогите+(+игрик-4)(игрик+4)=+(7х-2)(7х+2)=