Question

помогите решить.... Научная конференция проводится в 5 дней. Всего запланировано 75 докладов — первые три дня по 17 докладов, остальные распределены поровну между четвертым и пятым днями. Порядок докладов определяется жеребьёвкой. Какова вероятность, что доклад профессора М. окажется запланированным на последний день конференции?

Answer 1

В условии задание сказано что на конференции будет заслушано 75 докладов, первые три дня по 17 докладов, остальные распределены поровну между четвертым и пятым днями
найдем сколько  участников будут выступать в четвертый и пятый день 
1) (75-3·17)=24 участника будут выступать в четвертый и пятый день
2) 24:2=12 участника будут выступать в пятый день
$P= \frac{m}{n}$
m-число благоприятных исходов - 12
n-число всех элементарных исходов - 75
$P= \frac{12}{75} =0.16=$16%
ответ 16%

Answer 2

Probability of Professor M.'s Presentation on the Last Day of the Conference

To determine the probability of Professor M.'s presentation being scheduled on the last day of the conference, we need to consider the total number of presentations and the distribution of presentations across the conference days.

According to the information provided, there are a total of 75 presentations planned for the conference. The first three days will have 17 presentations each, while the remaining presentations will be evenly distributed between the fourth and fifth days.

To calculate the probability, we need to determine the number of presentations on the last day and divide it by the total number of presentations.

Let's calculate it step by step:

1. Calculate the total number of presentations on the last day: - The first three days will have a total of 17 presentations each, which is a total of 3 * 17 = 51 presentations. - Therefore, the remaining presentations for the last two days will be 75 - 51 = 24 presentations. - Since these presentations are evenly distributed between the fourth and fifth days, each day will have 24 / 2 = 12 presentations.

2. Calculate the probability of Professor M.'s presentation being scheduled on the last day: - Since the presentations are determined by a lottery, each presentation has an equal chance of being scheduled on any given day. - Therefore, the probability of Professor M.'s presentation being scheduled on the last day is the number of presentations on the last day divided by the total number of presentations. - The number of presentations on the last day is 12. - The total number of presentations is 75. - Therefore, the probability is 12 / 75 = 0.16 or 16%.

So, there is a 16% chance that Professor M.'s presentation will be scheduled on the last day of the conference.

Please let me know if you need any further assistance!