Question

2x^2+x-36=0 помогите плиз

Answer 1

Дискриминант равен 17

х1= 4,5
х2= -4

Answer 2

Solving the Quadratic Equation 2x^2 + x - 36 = 0

To solve the quadratic equation 2x^2 + x - 36 = 0, we can use the quadratic formula:

Quadratic Formula: The solutions to the quadratic equation ax^2 + bx + c = 0 are given by: \[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \]

Using the given equation 2x^2 + x - 36 = 0, we can identify the values of a, b, and c: - a = 2 - b = 1 - c = -36

Now, we can substitute these values into the quadratic formula to find the solutions for x.

Calculating the Solutions: \[ x = \frac{{-1 \pm \sqrt{{1^2 - 4*2*(-36)}}}}{{2*2}} \]

\[ x = \frac{{-1 \pm \sqrt{{1 + 288}}}}{{4}} \]

\[ x = \frac{{-1 \pm \sqrt{{289}}}}{{4}} \]

\[ x = \frac{{-1 \pm 17}}{{4}} \]

So, the solutions for the equation 2x^2 + x - 36 = 0 are: \[ x_1 = \frac{{-1 + 17}}{{4}} = 4 \] \[ x_2 = \frac{{-1 - 17}}{{4}} = -9 \]

Therefore, the solutions for the given quadratic equation are x = 4 and x = -9.