
В двух баках 140 л воды. Когда из первого бака взяли 26 л воды а из второго 60 л воды то в первом
баке осталось в два раза больше воды чем во втором. Сколько литров воды было в каждом баке первоначально?

Ответы на вопрос

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Problem Analysis
We are given two tanks with a total of 140 liters of water. From the first tank, 26 liters of water are taken, and from the second tank, 60 liters of water are taken. After this, the amount of water remaining in the first tank is twice the amount of water remaining in the second tank. We need to determine the initial amount of water in each tank.
Solution
Let's assume that the initial amount of water in the first tank is x liters and the initial amount of water in the second tank is y liters.
According to the given information: 1. From the first tank, 26 liters of water are taken, so the remaining water in the first tank is x - 26 liters. 2. From the second tank, 60 liters of water are taken, so the remaining water in the second tank is y - 60 liters. 3. The remaining water in the first tank is twice the remaining water in the second tank, so we have the equation: x - 26 = 2(y - 60).
To solve this equation, we can simplify it: x - 26 = 2y - 120
Now, let's solve for x in terms of y: x = 2y - 120 + 26 x = 2y - 94
Substituting this value of x into the equation x - 26 = 2(y - 60), we get: 2y - 94 - 26 = 2(y - 60) 2y - 120 = 2y - 120
This equation is true for any value of y. Therefore, we can conclude that the initial amount of water in each tank can be any value, as long as the total amount of water in both tanks is 140 liters.
In summary, the initial amount of water in each tank can vary, as long as the total amount of water in both tanks is 140 liters.


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