Question

(X-4b)(x²+4xb+16b²)+64b³+x³+b² при x= -1, b=2 решительно пожалуйста

Answer 1

Вот здесь я отправила, надеюсь тебе будет понятно

Answer 2

Solution for (x-4b)(x²+4xb+16b²)+64b³+x³+b² when x=-1 and b=2

To solve the given expression for the values of x and b, we can substitute the given values into the expression and simplify it step by step.

Substitute x=-1 and b=2 into the expression: (x-4b)(x²+4xb+16b²)+64b³+x³+b² = (-1 - 4*2)((-1)² + 4*(-1)*2 + 16*2²) + 64*2³ + (-1)³ + 2² = (-1 - 8)(1 - 8 + 64) + 64*8 + (-1) + 4 = (-9)(57) + 512 + (-1) + 4 = -513 + 515 = 2

So, the value of the expression when x=-1 and b=2 is 2.