
Решите как можно быстрее системы. Х-6у=-2 2х+3у=11 Ещё. 2х+у=-5 х-3у=-6


Ответы на вопрос

способом сложения:
x-6y= -2 / *(-2)
2x+3y=11
-2x+12y=4
2x+3y=11
15y=15
y=1
x=4
Ответ: (4;1)
2x+y=-5 /*3
x-3y=-6
6x+3y=-15
x-3y=-6
7x=-21
x=-3
y=1
Ответ: (-3;1)



х-6у=-2 х=6у-2
2х+3у=11 2(6у-2) + 3у = 11
2(6у-2)+3у=11
12у-4+3у=11
12у+3у=11+4
15у=15
у=15/15
у=1
х=6*1-2=4
Ответ. (4;1)
2х+у=-5 у=-5-2х
х-3у=-6 х-3(-5-2х)=-6
х-3(-5-2х)=-6
х+15+6х=-6
7х=-21
х=-3
у=-5-2*(-3) = -5+6=1
Ответ. (-3;1)



System of Equations
To solve the system of equations:
1. Equation 1: -6x + y = -2 2. Equation 2: 2x + 3y = 11 3. Equation 3: 2x + y = -5 4. Equation 4: x - 3y = -6
We can use various methods, such as substitution or elimination, to find the values of x and y that satisfy all the equations.
Method 1: Substitution
Let's solve the system of equations using the substitution method:
From Equation 1, we can express y in terms of x: -6x + y = -2 y = 6x - 2
Substituting this value of y into Equation 2: 2x + 3(6x - 2) = 11 2x + 18x - 6 = 11 20x = 17 x = 17/20
Substituting the value of x back into Equation 1 to find y: -6(17/20) + y = -2 -51/10 + y = -2 y = -2 + 51/10 y = -2/10 + 51/10 y = 49/10
Therefore, the solution to the system of equations is x = 17/20 and y = 49/10.
Method 2: Elimination
Let's solve the system of equations using the elimination method:
Multiplying Equation 1 by 2 and Equation 3 by -3 to eliminate the x term: -12x + 2y = -4 -6x - 3y = 15
Adding Equation 2 and Equation 4 to eliminate the x term: 2x + 3y + x - 3y = 11 - 6 3x = 5 x = 5/3
Substituting the value of x back into Equation 1 to find y: -6(5/3) + y = -2 -10 + y = -2 y = -2 + 10 y = 8
Therefore, the solution to the system of equations is x = 5/3 and y = 8.
Summary
Using the substitution method, the solution to the system of equations is x = 17/20 and y = 49/10. Using the elimination method, the solution is x = 5/3 and y = 8.
Please note that the search results provided by You.com did not directly provide the solution to this specific system of equations. However, the methods used to solve the system are standard algebraic techniques.


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