Question

Двое рабочих изготовили вместе 1020 деталей. Первый рабочий работал 15 дней, а второй - 14 дней. Сколько деталей изготовлял каждый рабочий за один день, если первый рабочий за 3 дня изготовлял на 60 деталей больше,чем второй за 2 дня?(Решение задачи с помощью системы двух уравнений с двумя неизвестными)

Answer 1

х -первый раб в день, у- второй тогда 15х+14у=1020 и 3х-2у=60, выразим х, х=(60+2у)/3, подставим в первое: 15*(60+2у)/3+14у=1020, 900+30у+42у=3060, у=2160/42, у=30, х= 40

Answer 2

Problem Analysis

To solve this problem, we can use a system of two equations with two unknowns. Let's denote the number of parts the first worker makes per day as x and the number of parts the second worker makes per day as y. We are given the following information: 1. The first worker worked for 15 days, and the second worker worked for 14 days. 2. Together, they made 1020 parts.

We are also given the additional information that the first worker made 60 more parts than the second worker in 3 days, which we can use to form another equation.

System of Equations

We can form the following system of equations based on the given information: 1. 15x + 14y = 1020 (equation representing the total number of parts made by both workers) 2. 3x - 2y = 60 (equation representing the additional information about the difference in parts made by the two workers in 3 days)

Solving the System of Equations

We can solve this system of equations to find the values of x and y.

Solution

Let's solve the system of equations to find the values of x and y.