Question

1/ √5+2 нужно избавиться от отрицательости в знаменателе

Answer 1

$\frac{1}{ \sqrt{5} +2} = \frac{1}{ \sqrt{5} +2}\cdot\frac{\sqrt{5} -2}{\sqrt{5} -2}=\frac{\sqrt{5} -2}{(\sqrt{5} -2)(\sqrt{5} +2)}=\frac{\sqrt{5} -2}{(\sqrt{5} )^2-2^2}= \sqrt{5} -2$

Answer 2

Solving 1/(√5 + 2) to Remove Negativity in the Denominator

To solve the expression 1/(√5 + 2) and remove the negativity in the denominator, we can rationalize the denominator. Rationalizing the denominator involves multiplying the numerator and denominator by a suitable expression to eliminate the radical in the denominator.

Rationalizing the Denominator: To rationalize the denominator of the expression 1/(√5 + 2), we can multiply the numerator and denominator by the conjugate of the denominator, which is √5 - 2.

Calculation: 1/(√5 + 2) * (√5 - 2)/(√5 - 2)

This will result in a rationalized expression without a radical in the denominator.

Result of Rationalization:

The result of rationalizing the denominator of the expression 1/(√5 + 2) is: (√5 - 2)/(5 - 4)

Conclusion:

By rationalizing the denominator, we have successfully removed the negativity in the denominator of the expression 1/(√5 + 2).