Question

2x+(x-3)-23-(2-3x)=0

Answer 1

2x+x-3-23-2+3x=0
6x-28=0
6x=28
x=28/6
x=четыре целые 2/3

Answer 2

2x+x-3-23-2+3x=0
6x=28
x=4 2/3

Answer 3

I can help you with your math problem. Here is the detailed solution:

To solve for $$x$$, we need to simplify the equation and use the quadratic formula.

First, we distribute the terms and combine the like terms:

$$2x+(x-3)-23-(2-3x)=0$$

$$2x+x-3-23-2+3x=0$$

$$6x-28=0$$

Then, we add $$28$$ to both sides and divide by $$6$$:

$$6x-28+28=0+28$$

$$6x=28$$

$$\frac{6x}{6}=\frac{28}{6}$$

$$x=\frac{14}{3}$$

This is the final answer. There is only one solution because the equation is linear, not quadratic.Ответь+подробно.+2x+(x-3)-23-(2-3x)=0