Question

ПОМОГИТЕ :3 Найдите значение выражения cd/ d - c(d/c - 2 + c/d) при d = 5 - корень из 3, с = - корень из 3 (cd/ d - c(d/c - 2 + c/d) при d = 5 - ^3 , с = - ^3)

Answer 1

$\frac{cd}{c} - c( \frac{d}{c} -2+ \frac{c}{d})=d-d+2c- \frac{ c^{2} }{d}= 2c- \frac{ c^{2} }{d}$
$-2 \sqrt{3} - \frac{3}{5- \sqrt{3}}=-2 \sqrt{3}-3$

Answer 2

I can help you with your math problem. Here is the solution:

First, let's rewrite the expression using LaTeX:

$$\frac{cd}{d} - c\left(\frac{d}{c} - 2 + \frac{c}{d}\right)$$

Next, let's substitute the values of $d$ and $c$:

$$\frac{(-\sqrt{3})(5 - \sqrt{3})}{5 - \sqrt{3}} - (-\sqrt{3})\left(\frac{5 - \sqrt{3}}{-\sqrt{3}} - 2 + \frac{-\sqrt{3}}{5 - \sqrt{3}}\right)$$

Now, let's simplify the expression by canceling out the common factors and applying the distributive property:

$$-\sqrt{3} + \sqrt{3}\left(-\sqrt{3} + 2 + \frac{\sqrt{3}}{5 - \sqrt{3}}\right)$$

$$-\sqrt{3} - 3 + 2\sqrt{3} + \frac{3}{5 - \sqrt{3}}$$

Finally, let's combine the like terms and rationalize the denominator:

$$-\sqrt{3} - 3 + 2\sqrt{3} + \frac{3}{5 - \sqrt{3}}$$

$$-\sqrt{3} - 3 + 2\sqrt{3} + \frac{3(5 + \sqrt{3})}{(5 - \sqrt{3})(5 + \sqrt{3})}$$

$$-\sqrt{3} - 3 + 2\sqrt{3} + \frac{15 + 3\sqrt{3}}{22}$$

$$-\frac{9}{22} + \frac{25\sqrt{3}}{22}$$

Therefore, the value of the expression is $-\frac{9}{22} + \frac{25\sqrt{3}}{22}$. I hope this helps. :)Ответь+подробно.+ПОМОГИТЕ+:3+Найдите+значение+выражения+cd/+d+-+c(d/c+-+2+++c/d)+при+d+=+5+-+корень+из+3,+с+=+-+корень+из+3+(cd/+d+-+c(d/c+-+2+++c/d)+при+d+=+5+-+^3+,+с+=+-+^3)