Question

x-y=2 3x-y²=6 системное уравнение

Answer 1

Решение во вложениии..!

 

Answer 2

х=2+у

3(2+у)-у^2=6

6+6у-у^2-6=0

-у^2+6y=0       *(-1)

y^2-6y=0

y(y-6)=0

y1=0     или y=6

 

x1=2     x2=2+6=8

 

Ответ: (2;0) (8;6)

Answer 3

Solving the System of Equations

To solve the system of equations x-y=2 and 3x-y²=6, we can use the substitution method or the elimination method. Let's use the substitution method to solve this system of equations.

First, we can solve the first equation for x in terms of y: x = y + 2.

Next, we can substitute this expression for x into the second equation: 3(y + 2) - y² = 6.

Solving this equation will give us the values of x and y that satisfy both equations.

Solution

By solving the equation 3(y + 2) - y² = 6, we find that the solutions for x and y are: x = 1, y = -1 and x = 4, y = 2.

Therefore, the solutions to the system of equations x-y=2 and 3x-y²=6 are (1, -1) and (4, 2).

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