Question

Найдите множество корней уравнения (6-2x)^2 = 3x - 9 без Дискримината!!!! молю

Answer 1

36-24x+4x²-3x+9=0
4x²-27x+45=0
D=729-720=9
x1=(27-3)/8=3
x2=(27+3)/8=15/4

Answer 2

Надеюсь, что все правильно. удачи :)

Answer 3

Solving the Equation without Discriminant

To find the roots of the equation (6-2x)^2 = 3x - 9 without using the discriminant, we can simplify the equation and solve for x.

Let's start by expanding the square on the left side of the equation:

(6-2x)^2 = 3x - 9

Expanding the square gives us:

36 - 24x + 4x^2 = 3x - 9

Rearranging the terms:

4x^2 - 27x + 45 = 0

Now, we have a quadratic equation. To solve it without using the discriminant, we can try factoring or completing the square.

Let's try factoring the quadratic equation:

4x^2 - 27x + 45 = 0

Factoring the equation, we get:

(2x - 5)(2x - 9) = 0

Setting each factor equal to zero, we have:

2x - 5 = 0 or 2x - 9 = 0

Solving for x in each equation:

2x - 5 = 0: Adding 5 to both sides: 2x = 5 Dividing both sides by 2: x = 5/2

2x - 9 = 0: Adding 9 to both sides: 2x = 9 Dividing both sides by 2: x = 9/2

Therefore, the equation (6-2x)^2 = 3x - 9 has two solutions: x = 5/2 and x = 9/2.

Please note that these solutions have been obtained without using the discriminant.

Let me know if there's anything else I can help you with!