Question

49х2-28х-3=-7 помогите пожалуйста

Answer 1

49x^2-28x-3=-7
49x^2-28x+4=0
D=28^2-4*4*49=784-784=0
x=28/98=14/49=2/7

Answer 2

Solving the Equation

To solve the equation 49x^2 - 28x - 3 = -7, we can follow these steps:

1. Combine Like Terms: Combine the constants on the right side of the equation. 2. Standard Form: Rewrite the equation in standard form (ax^2 + bx + c = 0). 3. Quadratic Formula: Use the quadratic formula to solve for x.

Step 1: Combine Like Terms

First, let's combine the constants on the right side of the equation: 49x^2 - 28x - 3 + 7 = 0

This simplifies to: 49x^2 - 28x + 4 = 0

Step 2: Standard Form

Now, the equation is in standard form: 49x^2 - 28x + 4 = 0

Step 3: Quadratic Formula

We can use the quadratic formula to solve for x: x = (-b ± √(b^2 - 4ac)) / (2a)

Where: - a = 49 - b = -28 - c = 4

Plugging these values into the quadratic formula, we get: x = (-(-28) ± √((-28)^2 - 4*49*4)) / (2*49) x = (28 ± √(784 - 784)) / 98 x = (28 ± √0) / 98 x = 28 / 98 x = 2 / 7

So, the solution to the equation 49x^2 - 28x + 4 = 0 is x = 2/7.