Question

Решите пожалуйста задачу.За 2 альбома и 5 тетрадей Маша заплатила 9 грн.Сколько 1 альбом и сколько стоет одна тетрадь,если 3 тетради дороже от 1 альбома на 1 грн.

Answer 1

Пусть х-стоимость тетради,тогда у- стоимость альбома.

(2у+5х=9

(3х-у=1|×2

(2у+5х=9

(6х-2у=2

2у+5х+6х-2у=11

11х=11

х=11

(х=11

(3х-у=1

33-у=1

у=32

Answer 2

Problem Analysis

We are given the information that Masha paid 9 UAH for 2 albums and 5 notebooks. We need to determine the cost of one album and one notebook, given that 3 notebooks are more expensive than one album by 1 UAH.

Solution

Let's assume the cost of one album is A UAH and the cost of one notebook is N UAH.

From the given information, we can form the following equations: Equation 1: 2A + 5N = 9 (since Masha paid 9 UAH for 2 albums and 5 notebooks) Equation 2: 3N = A + 1 (since 3 notebooks are more expensive than one album by 1 UAH)

To solve this system of equations, we can use substitution or elimination method. Let's use the substitution method.

From Equation 2, we can express A in terms of N: A = 3N - 1

Substituting this value of A in Equation 1, we get: 2(3N - 1) + 5N = 9 6N - 2 + 5N = 9 11N - 2 = 9 11N = 11 N = 1

Now, substituting the value of N back into Equation 2, we can find the value of A: A = 3(1) - 1 A = 3 - 1 A = 2

Therefore, the cost of one album is 2 UAH and the cost of one notebook is 1 UAH.

Answer

Based on the given information, one album costs 2 UAH and one notebook costs 1 UAH.