Question

Докажите, что при любых переменных выполняется неравенство.

Answer 1

$\frac{6 \sqrt{y^2+3}-(y^2+12) }{y^2+12} \leq 0$
$\frac{-6 \sqrt{y^2+3}+(y^2+3)+9}{y^2+12} \geq 0$
$\frac{ (\sqrt{y^2+3}+3) ^2}{y^2+12} \geq 0$
числитель дроби неотрицателен при любом значении у, знаменатель дроби положителен при любом значении у, значит дробь при любом значении у принимает неотрицательные значения, ч.т.д

Answer 2

Proof of Inequality

To prove that the inequality holds for any variables, we need to consider the specific inequality mentioned in the question. However, the question does not provide a specific inequality to prove. Therefore, without a specific inequality, it is not possible to provide a proof.

If you have a specific inequality in mind, please provide it, and I will be happy to help you with the proof.