Question

(х+5)(х-6)-4х=-(х^+2) помогите

Answer 1

(х+5)(х-6)-4х=-(х²+2) 
х²-6х+5х-30-4х=-х²-2 
2х²-5х-28=0 
D=25+224=249 
х₁=(5-√249)/4 
х₂=(5+√249)/4

Answer 2

I can help you with your math problem. Here is the detailed solution:

First, expand the brackets: $(x+5)(x-6)-4x=-(x^2)$

Then, simplify the equation: $x^2-11x-30-4x=-(x^2)$

Next, move all the terms to one side: $2x^2-15x-30=0$

Finally, factor the quadratic equation: $(2x+3)(x-10)=0$

The solutions are $x=-\frac{3}{2}$ or $x=10$.

I hope this helps.Ответь+подробно.+(х+5)(х-6)-4х=-(х^+2)+помогите