Question

(a⁵-3b⁶)(a¹⁰+3a⁵b⁶+9b¹²)m³+n¹⁰)(m⁶-m³n¹⁰+n²⁰)Помогитеее срочнооо​

Answer 1

Ответ:

Объяснение:формула разность и сумма кубов

(а-в)(а²+ав+в²)= а³-в³               (а+в)(а²-ав+в²)= а³+в³

(a⁵-3b⁶)(a¹⁰+3a⁵b⁶+9b¹²)=(а⁵)³ - (3b⁶)³= a¹⁵- 27b¹⁸

(m³+n¹⁰)(m⁶-m³n¹⁰+n²⁰)=(m³)³+ (n¹⁰)³= m⁹ + n³⁰

Answer 2

Multiplying Polynomials

To solve the given expression, we can use the distributive property to multiply the terms of the first polynomial by each term of the second polynomial. Let's break it down step by step.

Step 1: Multiply (a⁵-3b⁶) by (a¹⁰+3a⁵b⁶+9b¹²)

First, we'll multiply each term in the first polynomial by each term in the second polynomial.

1. Multiply a⁵ by a¹⁰, a⁵ by 3a⁵b⁶, a⁵ by 9b¹². 2. Multiply -3b⁶ by a¹⁰, -3b⁶ by 3a⁵b⁶, -3b⁶ by 9b¹².

Step 2: Multiply the result from Step 1 by (m⁶-m³n¹⁰+n²⁰)

Once we have the result from Step 1, we'll multiply it by the third polynomial.

1. Multiply each term obtained from Step 1 by m⁶. 2. Multiply each term obtained from Step 1 by -m³n¹⁰. 3. Multiply each term obtained from Step 1 by n²⁰.

Let's calculate each step and simplify the expression.

Calculation

1. Multiply (a⁵-3b⁶) by (a¹⁰+3a⁵b⁶+9b¹²):

- a⁵ * a¹⁰ = a¹⁵ - a⁵ * 3a⁵b⁶ = 3a¹⁰b⁶ - a⁵ * 9b¹² = 9a⁵b¹² - -3b⁶ * a¹⁰ = -3a¹⁰b⁶ - -3b⁶ * 3a⁵b⁶ = -9a⁵b¹² - -3b⁶ * 9b¹² = -27b¹⁸

2. Multiply the result from Step 1 by (m⁶-m³n¹⁰+n²⁰):

- (a¹⁵+3a¹⁰b⁶+9a⁵b¹²-3a¹⁰b⁶-9a⁵b¹²-27b¹⁸)m⁶ - -3a¹⁰b⁶m³n¹⁰ - 9b¹²n²⁰

Simplified Expression

After simplifying the expression, we get:

a¹⁵m⁶ - 3a¹⁰b⁶m³n¹⁰ - 27b¹⁸m⁶ + 9b¹²n²⁰

This is the simplified result of the given expression.