Question

Човен плив за течією річки 2,6 год і проти течії - 3,2 год. Шлях, який човен пройшов за течією, на 0,4 км довший, ніж шлях, який пройшов човен проти течії. Знайдіть власну швидкість човна, якщо швидкість течії становить 1 км/год. УМОЛЯЮ , ПОМОГИТЕ СРОЧНО!!

Answer 1

I will try to answer your question in detail. Let x be the speed of the boat in still water, and 1 km/h be the speed of the current. Then the speed of the boat downstream is x + 1 km/h, and the speed of the boat upstream is x - 1 km/h. The distance that the boat traveled downstream is 2.6 * (x + 1) km, and the distance that the boat traveled upstream is 3.2 * (x - 1) km. According to the problem, the distance downstream is 0.4 km longer than the distance upstream, so we can write an equation:

2.6 * (x + 1) = 3.2 * (x - 1) + 0.4

Expanding and simplifying, we get:

2.6x + 2.6 = 3.2x - 3.2 + 0.4 0.6x = 6.4 x = 6.4 / 0.6 x = 10.67

Therefore, the speed of the boat in still water is 10.67 km/h. I hope this helps you.