Question

Последовательность (bn) геометрическая прогрессия b6=3, q=3 найти b1

Answer 1

B 6 = b1·q^5
3 = b1·3^5
b1` = 3:3^5
b1 = 1/3^4= 1/81

Answer 2

Finding b1 in a Geometric Progression

To find b1 in a geometric progression given b6=3 and q=3, we can use the formula for the nth term of a geometric progression: \(b_n = b_1 \times q^{(n-1)}\). We can then solve for b1 using the given values of b6 and q.

Using the formula \(b_n = b_1 \times q^{(n-1)}\), we can substitute the given values: \(b_6 = b_1 \times 3^{(6-1)} = 3\)

Solving for b1: \(b_1 = \frac{b_6}{3^{(6-1)}}\)

Substituting the values of b6 and q: \(b_1 = \frac{3}{3^5} = \frac{3}{243} = \frac{1}{81}\)

So, b1 = 1/81.