Question

A) cos(180°-a)=?b) tg(3pi/2+a)=?​

Answer 1

Отметьте пожалуйста лучшим решением и поставьте сердечко

Answer 2

A) cos(180° - a) = cos(180°)cos(a) + sin(180°)sin(a)

Remember that cos(180°) = -1 and sin(180°) = 0. So, the expression becomes:

cos(180° - a) = (-1)cos(a) + 0sin(a) = -cos(a)

B) tg(3π/2 + a) = tan(3π/2) + tan(a)

First, let's find the values of tangent for 3π/2 and then add the value of tan(a):

1. tan(3π/2) = tan(π/2) = undefined, as the tangent of π/2 is undefined due to the vertical asymptote.

So, tg(3π/2 + a) is also undefined, assuming that a is any real number.