Question

А)log2 14 – log2 7; б) log3 36 – log3 8/27+ log3 18 в) 6log⁶27срочно ​

Answer 1

Ответ:

а)1 б)7

Объяснение:

Answer 2

А) log2 14 – log2 7: To solve this expression, we can use the logarithmic property that states log(a) - log(b) = log(a/b). Applying this property, we can rewrite the expression as log2(14/7). Simplifying further, we get log2(2), which equals 1. Therefore, the value of log2 14 – log2 7 is 1.

б) log3 36 – log3 (8/27) + log3 18: Using the same logarithmic property as before, we can rewrite the expression as log3(36/(8/27)) + log3 18. Simplifying further, we have log3(36 * (27/8)) + log3 18. This can be simplified to log3(9 * 27) + log3 18, which becomes log3(243) + log3 18. Finally, we can combine the two logarithms using the property log(a) + log(b) = log(a * b), resulting in log3(243 * 18). Simplifying this expression gives us log3(4374), which is approximately equal to 5.14.

в) 6log⁶27: To solve this expression, we can use the logarithmic property log(a^b) = b * log(a). Applying this property, we have 6 * log⁶27 = 6 * 6 * log27. Simplifying further, we get 36 * log27. Since log27 is equal to 3 (since 3^3 = 27), we can substitute this value into the expression, giving us 36 * 3 = 108.

I hope this helps! Let me know if you have any further questions.