Question

На бал пришли 35 мальчиков и 18 девочек. Некоторые мальчики потанцевали с некоторыми девочками (не более одного раза в каждой паре). После бала каждый человек рассказал родителям, сколько раз он танцевал. Какое наибольшее количество различных чисел дети могли назвать?

Answer 1

Ответ:

36

Объяснение:

Всего может быть 36 неодинаковых чисел (от 0 до 35)

Answer 2

Problem Analysis

In this problem, we are given that 35 boys and 18 girls attended a ball. Some boys danced with some girls, but no more than once in each pair. After the ball, each person told their parents how many times they danced. We need to determine the maximum number of different numbers the children could have named.

Solution

To find the maximum number of different numbers the children could have named, we need to consider the possible combinations of boys and girls dancing together.

Let's analyze the problem step by step:

1. The maximum number of different numbers the children could have named will be the sum of the number of boys and the number of girls, minus the number of pairs that danced together.

2. The number of pairs that danced together will be the minimum of the number of boys and the number of girls.

3. In this case, the number of pairs that danced together will be 18 (the number of girls), as there are fewer girls than boys.

4. Therefore, the maximum number of different numbers the children could have named is 35 + 18 - 18 = 35.

The maximum number of different numbers the children could have named is 35.

Conclusion

In this problem, we determined that the maximum number of different numbers the children could have named is 35. This was calculated by adding the number of boys and girls and subtracting the number of pairs that danced together.