Question

Ребята,помогите решить по скорому.Очень надо! (Можно в расписанном виде) (3x-1)*(x-2)=x-2x(x-4) (2x-1)^2+4x=10 (3x-1)*(3x+1)=26 Заранее спасибо :)

Answer 1

1) 3х²-6х-х+2=х-2х²-8х
3х²+2х²-6х+8х-х-х+2=0
5х²+2=0
5х²=-2
х²=-2/5
нет решения (потому что х² не может быть отрицательным)

2)4х²-4х+1+4х=10
4х²+1-10=0
4х²-9=0
4х²=9
х²=9/4
х= ±√9/4=±3/2

3)9х²+3х-3х-1-26=0
9х²-27=0
9х²=27
х²=27/9=3
х= ±√3

Answer 2

#### Equation 1: (3x-1)*(x-2)=x-2x(x-4)+(2x-1)^2+4x=10 To solve the equation (3x-1)*(x-2)=x-2x(x-4)+(2x-1)^2+4x=10, we will simplify and solve step by step. 1. Simplify the equation: (3x-1)*(x-2) = x - 2x(x-4) + (2x-1)^2 + 4x = 10 2. Expand and simplify the equation: (3x^2 - 7x + 2) = x - 2x^2 + 8x - 16 + 4x^2 - 4x + 1 + 4x = 10 3. Combine like terms: 3x^2 - 7x + 2 = x - 2x^2 + 8x - 16 + 4x^2 - 4x + 1 + 4x = 10 4. Rearrange the equation to bring all terms to one side: 3x^2 - 7x + 2 - x + 2x^2 - 8x + 16 - 4x^2 + 4x - 1 - 4x - 10 = 0 5. Combine like terms: 3x^2 + 2x^2 - 4x^2 - 7x - x - 8x + 4x + 4x - 4x + 2 - 1 + 16 - 10 = 0 6. Simplify the equation: 5x^2 - 11x + 7 = 0 Now, we can solve this quadratic equation. 7. Use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a) For the equation 5x^2 - 11x + 7 = 0, the values of a, b, and c are: a = 5, b = -11, c = 7 Substituting these values into the quadratic formula, we get: x = (-(-11) ± √((-11)^2 - 4 * 5 * 7)) / (2 * 5) Simplifying further: x = (11 ± √(121 - 140)) / 10 x = (11 ± √(-19)) / 10 Since the discriminant (b^2 - 4ac) is negative, the equation has no real solutions. Therefore, there are no real values of x that satisfy the equation (3x-1)*(x-2)=x-2x(x-4)+(2x-1)^2+4x=10. #### Equation 2: (3x-1)*(3x+1)=26 To solve the equation (3x-1)*(3x+1)=26, we will simplify and solve step by step. 1. Simplify the equation: (3x-1)*(3x+1) = 26 2. Expand and simplify the equation: 9x^2 - x - 3x + 1 = 26 3. Combine like terms: 9x^2 - 4x + 1 = 26 4. Rearrange the equation to bring all terms to one side: 9x^2 - 4x + 1 - 26 = 0 5. Combine like terms: 9x^2 - 4x - 25 = 0 Now, we can solve this quadratic equation. 6. Use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a) For the equation 9x^2 - 4x - 25 = 0, the values of a, b, and c are: a = 9, b = -4, c = -25 Substituting these values into the quadratic formula, we get: x = (-(-4) ± √((-4)^2 - 4 * 9 * -25)) / (2 * 9) Simplifying further: x = (4 ± √(16 + 900)) / 18 x = (4 ± √916) / 18 Since √916 is approximately 30.27, we have two possible solutions: x = (4 + 30.27) / 18 ≈ 2.69 x = (4 - 30.27) / 18 ≈ -1.26 Therefore, the solutions to the equation (3x-1)*(3x+1)=26 are approximately x = 2.69 and x = -1.26. Please let me know if you need any further assistance!