Question

(3х-1)(2х+7)-16=(х+1)(6х-5)помогите ​

Answer 1

Ответ:

(3x-1)(2x+7)-16=(x+1)(6x-5)

6x^2 + 13x - 2x - 7 - 16 = 6x^2 - 5x + x + 1

6x^2 + 11x - 23 = 6x^2 - 4x + 1

11x - 23 = -4x + 1

15x - 23 = 1

15x = 24

x = 8/5

Объяснение:

Answer 2

Sure thing! Let's solve the equation step by step. First, let's expand and simplify both sides:

On the left side: $(3x-1)(2x+7)-16$

Using the distributive property: $6x^2 + 21x - 2x - 7 - 16$

Combine like terms: $6x^2 + 19x - 23$

On the right side: $(x+1)(6x-5)$

Using the distributive property: $6x^2 - 5x + 6x - 5$

Combine like terms: $6x^2 + x - 5$

Now, the equation becomes: $6x^2 + 19x - 23 = 6x^2 + x - 5$

Subtract $6x^2$ from both sides to simplify: $19x - 23 = x - 5$

Subtract $x$ from both sides: $18x - 23 = -5$

Add 23 to both sides: $18x = 18$

Divide by 18 to solve for $x$: $x = 1$

So, the solution to the equation is $x = 1$.