Question

4(х+3)^2 - (х+2)^2 = 3х^2 - 8

Answer 1

Ответ:

x=-2

Объяснение:

=3x^2+20x+32=3x^2-8

20x+32=-8

20x=-8-32

20x=-40

x=-2

Answer 2

To solve the equation 4(x+3)^2 - (x+2)^2 = 3x^2 - 8, you can follow these steps:

1. Expand and simplify the left side of the equation:

   4(x+3)^2 - (x+2)^2 = 4(x^2 + 6x + 9) - (x^2 + 4x + 4)

   Expand each term:

   4x^2 + 24x + 36 - (x^2 + 4x + 4)

   Now, subtract the second expression from the first:

   4x^2 + 24x + 36 - x^2 - 4x - 4

   This simplifies to:

   3x^2 + 20x + 32

2. Now, the equation becomes:

   3x^2 + 20x + 32 = 3x^2 - 8

3. You can see that the 3x^2 terms on both sides of the equation will cancel out. So, you're left with a linear equation:

   20x + 32 = -8

4. Subtract 32 from both sides to isolate the x term:

   20x = -8 - 32 20x = -40

5. Finally, divide both sides by 20 to solve for x:

   x = -40 / 20 x = -2

So, the solution to the equation is x = -2.