Question

1-sin*2a/sin*x-cos*x=​

Answer 1

$\dfrac{1-sin2a}{sina-cosa}=\dfrac{sin^2a+cos^2a-2\, sina\cdot cosa}{sina-cosa}=\dfrac{(sina-cosa)^2}{sina-cosa}=sna-cosa$

Answer 2

It seems like you have an equation involving trigonometric functions, but it's a bit unclear due to the formatting. If you could provide more context or clarify the equation, I'd be happy to help you solve it.

Is your equation:

(1 - sin^2(a)) / (sin(x) - cos(x)) = ?

Please confirm, and I'll assist you in solving it.