Question

-4x^2 +2x+6=-2x+3x-(-3+2x^2)

Answer 1

Ответ:

-4x^2 +2x+6=-2x+3x-(-3+2x^2)

-4х^2+2х+6=х+3-2х^2

2х^2-х-3=0

(2х-3)*(х+1)=0

2х-3=0. х+1=0

х1=3/2. х2=-1.

Answer 2

To solve the equation -4x^2 + 2x + 6 = -2x + 3x - (-3 + 2x^2), you'll need to simplify and then solve for x.

First, let's simplify the equation:

-4x^2 + 2x + 6 = -2x + 3x + (3 - 2x^2)

Now, let's combine like terms on both sides:

-4x^2 + 2x + 6 = x + 3 + 3

Simplify further:

-4x^2 + 2x + 6 = x + 6

Now, let's move all the terms to one side of the equation to set it to zero:

-4x^2 + 2x - x + 6 - 6 = 0

Combine like terms again:

-4x^2 + x = 0

Now, you have a quadratic equation. To solve for x, you can factor out the common factor, which is x:

x(-4x + 1) = 0

Now, you have two possibilities:

1. x = 0
2. -4x + 1 = 0

For the second possibility:

-4x + 1 = 0

Subtract 1 from both sides:

-4x = -1

Divide by -4:

x = (-1)/(-4)

x = 1/4

So, the solutions to the equation are:

x = 0 and x = 1/4.