Question

1.(a²+2ab+b²) - (a+b)²;2.(xy * yx) + (yz * yx). P.s - задание легкое , просто баллы раздаю.​

Answer 1

1. (a²+2ab+b²) - (a+b)²=  (a+b)² - (a+b)²=0

2. (xy * yx) + (yz * yx)=х²у²+у²хz.

Answer 2

1. (a² + 2ab + b²) - (a + b)² = a² + 2ab + b² - (a² + 2ab + b²)

Now, distribute the negative sign to each term inside the second set of parentheses:

= a² + 2ab + b² - a² - 2ab - b²

Now, you can simplify the expression by canceling out like terms:

= (a² - a²) + (2ab - 2ab) + (b² - b²)

The terms with 'a²' and 'b²' cancel out, leaving you with:

= 0 + 0 + 0

So, the result is 0.

2. (xy * yx) + (yz * yx)

In this expression, 'xy' and 'yx' are the same because multiplication is commutative. So, you can rewrite it as:

= (xy * xy) + (yz * yx)

Now, you have two terms to multiply:

= (x²y²) + (yz * yx)

Since 'yz' and 'yx' are different, you cannot simplify this further, so the expression remains:

= x²y² + yz * yx